获取所有Xorg显示的列表 [英] Obtaining List of all Xorg Displays
问题描述
我想知道如何获取系统上所有Xorg显示器的列表以及与每个显示器关联的屏幕的列表.我花了一些时间浏览Xlib文档,但找不到能满足我需要的功能.请假设除了POSIX兼容的OS和X外,我没有其他依赖项(例如,没有GTK).如果我要问的是假设这些最小的依赖关系是不可能的,那么使用其他库的解决方案就可以了.
I would like to know how I can obtain a list of all Xorg displays on my system, along with a list of screens associated with each display. I spent some time looking through the Xlib documentation, but was not able to find a function that does what I want. Please assume that I have no other dependencies other than a POSIX-complaint OS and X (e.g., no GTK). If what I ask is not possible assuming these minimal dependencies, then a solution using other libraries is fine.
非常感谢您的帮助!
推荐答案
我知道获取显示列表的唯一方法是检查/tmp/.X11-unix
目录.
The only way I know of to get a list of displays is to check the /tmp/.X11-unix
directory.
完成此操作后,您可以使用Xlib查询每个显示以获取更多信息.
Once you do that, you can use Xlib to query each display for more information.
每个示例:
#include <stdio.h>
#include <dirent.h>
#include <string.h>
#include <X11/Xlib.h>
int main(void) {
DIR* d = opendir("/tmp/.X11-unix");
if (d != NULL) {
struct dirent *dr;
while ((dr = readdir(d)) != NULL) {
if (dr->d_name[0] != 'X')
continue;
char display_name[64] = ":";
strcat(display_name, dr->d_name + 1);
Display *disp = XOpenDisplay(display_name);
if (disp != NULL) {
int count = XScreenCount(disp);
printf("Display %s has %d screens\n",
display_name, count);
int i;
for (i=0; i<count; i++)
printf(" %d: %dx%d\n",
i, XDisplayWidth(disp, i), XDisplayHeight(disp, i));
XCloseDisplay(disp);
}
}
closedir(d);
}
return 0;
}
运行上面的命令可以为我提供当前显示/屏幕的输出:
Running the above gives me this output with my current displays/screens:
Display :0 has 1 screens
0: 3046x1050
Display :1 has 2 screens
0: 1366x768
1: 1680x1050
除此以外,没有找到更好的方法来列出X显示.我非常想知道是否还有更好的选择.
Never found a better way of listing X displays other than that. I'd very much like to know if any better alternative exists.
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