$(uname -a)在Docker主机或任何Docker容器中返回相同的值 [英] $(uname -a) returning the same in docker host or any docker container

问题描述

为什么$(uname -a)返回与Docker容器内的主机相同的Linux内核?

Why $(uname -a) returns the same Linux kernel than the host machine inside a docker container?

uname -a
#=> Linux leo 3.13.0-55-generic #94-Ubuntu SMP Thu Jun 18 00:27:10 UTC 2015 x86_64 x86_64 x86_64 GNU/Linux

docker run -ti --rm ubuntu:vivid-20150611 uname -a
#=> Linux 147c3aff216b 3.13.0-55-generic #94-Ubuntu SMP Thu Jun 18 00:27:10 UTC 2015 x86_64 x86_64 x86_64 GNU/Linux

即使我的主机是Ubuntu 14.04(可信任)，而容器是Ubuntu 15.04(vivid)，并且应该具有3.19内核

Even though my host machine is Ubuntu 14.04 (trusty) while the container is Ubuntu 15.04 (vivid) and should have kernel 3.19

推荐答案

Docker使用主机操作系统内核，容器内没有自定义或其他内核.在计算机上运行的所有容器都共享此主机"内核.

Docker uses the host operating system kernel, there is no custom or additional kernel inside the container. All containers running on the machine are sharing this "host" kernel.

有关更多信息，请参见此问题.

See for more information this question on SuperUser.

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