如何获得巨大页面尺寸的价值? [英] How to get the value of huge page size?

问题描述

我希望直接从C代码中获取巨大页面大小的值，而无需运行bash命令.

I am looking to get the value of huge page size directly from my C code without to run a bash command.

我可以通过bash做到这一点

From bash i can do this

grep pse /proc/cpuinfo    > /dev/null && echo '2M huge page size are supported'
grep pdpe1gb /proc/cpuinfo> /dev/null && echo '1G huge page size are supported'

其次，如何使用具有1G巨大页面大小的mmap?

Secondly how to use mmap with 1G huge page size ?

谢谢

更新

代码段

#include <stdio.h>
#include <limits.h>
#include <hugetlbfs.h>

int main(void){
    long result1 = gethugepagesize(); 
    printf( "%d\n", result1 );
    long result2 = gethugepagesizes( NULL, 0);
    printf( "%d\n", result2 );
    long result3 = getpagesizes( NULL, 0);
    printf( "%d\n", result3 );
    printf("%d\n", PF_LINUX_HUGETLB);
    return 0;
}

输出

2097152
1
2
1048576

这里gethugepagesize返回2 Mb 1Gb的大页面怎么办?

here gethugepagesize return 2 Mb what about 1Gb huge page ?

推荐答案

尝试一下.

#include <hugetlbfs.h>
int getpagesizes(long pagesizes[], int n_elem); 

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