液体和算术 [英] Liquid and Arithmetic

问题描述

我正在做一些分页，我想知道是否有一种方法可以告诉液体只显示5页.我正在寻找的输出是

I am working on some pagination and I am wondering if there is a way to tell liquid to only show 5 pages. The output I am looking for is

<<前5 6 7 8 9后>>

<< First 5 6 7 8 9 Last >>

我目前使用的逻辑有效，但是它显示了全部30个页面.

The logic I currently have in place works but it is showing all 30 some pages.

{% for count in (2..paginator.total_pages) %}
    {% if count == paginator.page %}
        <span class="current">{{ count }}</span>
    {% else %}
        <a href="/page/{{ count }}/" class="pagenavi-page" title="{{ count }}">{{ count }}</a>
    {% endif %}
{% endfor %}

我希望能够使2和paginator.total_pages动态化，我已经尝试过

I would like to be able to make the 2 and paginator.total_pages be dynamic, I have tried

{% for count in ((paginator.page - 2)..(paginator.page + 2)) %} 

但是，此代码实际上并未进行数学运算，如果paginator.page = 5，则循环为5..5，并且不提供预期的结果.我可以弄清楚逻辑，这样它就不会达到负数并且可以按预期工作，但是我该怎么做数学方程式呢?

This code however does not actually do the math, if paginator.page = 5 then the loop is 5..5 and does not provide the expected results. I can figure out the logic so that it does not hit negative numbers and works as expected but how can I do math equations in this?

推荐答案

您需要在paginator.total_pages上使用过滤器进行算术运算，然后使用capture标记将结果捕获到变量中.一旦有了起始页和结束页，就可以像通常那样编写for循环:

You need use a filter on paginator.total_pages to do the arithmetic, and then capture the result in a variable using the capture tag. Once you have the start and end pages, you can write the for loop as you normally would:

{% capture page_start %}{{ paginator.page | minus: 2 }}{% endcapture %}
{% capture page_end %}{{ paginator.page | plus: 2 }}{% endcapture %}

{% for count in (page_start..page_end) %}
     {% comment %} ... do your thing ... {% endcomment %}
{% endfor %}

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