获取Lisp列表中列表的索引 [英] Get index of list within list in Lisp

问题描述

如果我有这样的列表

((0 1 2) (3 4 5) (6 7 8) (0 3 6) (1 3 7) (2 4 8) (0 4 8) (2 4 6))

我想找到(0 3 6)的索引，是否有内置函数可以执行此操作?当搜索项本身是列表时，POSITION似乎不起作用.

And I want to find the index of (0 3 6), is there a built-in function to do this? POSITION doesn't seem to work when the search item is itself a list.

推荐答案

请参见 hyperspec . POSITION可以采用:test参数:

See hyperspec. POSITION can take a :test argument:

(position '(0 3 6)
          '((0 1 2) (3 4 5) (6 7 8) (0 3 6) (1 3 7) (2 4 8) (0 4 8) (2 4 6))
          :test #'equal))
3

顺便说一下，POSITION(以及其他序列操作)的默认测试是EQL.

The default test for POSITION (and other sequence operations) is EQL, by the way.

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