sorted(list)和list.sort()有什么区别? [英] What is the difference between `sorted(list)` vs `list.sort()`?

问题描述

list.sort()对列表进行排序并替换原始列表，而sorted(list)返回列表的排序后的副本，而不更改原始列表.

list.sort() sorts the list and replaces the original list, whereas sorted(list) returns a sorted copy of the list, without changing the original list.

• 何时优先选择另一个?
• 哪个更有效率?多少钱?
• 执行list.sort()后，列表可以恢复为未排序状态吗?

• When is one preferred over the other?
• Which is more efficient? By how much?
• Can a list be reverted to the unsorted state after list.sort() has been performed?

推荐答案

sorted()返回一个 new 排序列表，而原始列表不受影响. list.sort()对列表进行就地排序，使列表索引突变，并返回None(类似于所有就地操作).

sorted() returns a new sorted list, leaving the original list unaffected. list.sort() sorts the list in-place, mutating the list indices, and returns None (like all in-place operations).

sorted()可用于任何可迭代的对象，而不仅限于列表.字符串，元组，字典(您将获得键)，生成器等，返回包含所有已排序元素的列表.

sorted() works on any iterable, not just lists. Strings, tuples, dictionaries (you'll get the keys), generators, etc., returning a list containing all elements, sorted.

• 要更改列表时使用list.sort()，要返回新的排序对象时使用sorted().如果要对可迭代的内容而不是列表还进行排序，请使用sorted().

• Use list.sort() when you want to mutate the list, sorted() when you want a new sorted object back. Use sorted() when you want to sort something that is an iterable, not a list yet.

对于列表，list.sort()比sorted()快，因为它不必创建副本.对于其他任何迭代，您别无选择.

For lists, list.sort() is faster than sorted() because it doesn't have to create a copy. For any other iterable, you have no choice.

否，您无法检索原始位置.呼叫list.sort()后，原始订单就消失了.

No, you cannot retrieve the original positions. Once you called list.sort() the original order is gone.

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