Python:确定列表中的所有项目是否都相同 [英] Python: determine if all items of a list are the same item

问题描述

在我的某些代码中，我将一系列对象放入列表中，并根据其属性(即字符串)构建了另一个列表.我需要确定第二个列表中的所有项目是否都具有完全相同的值，而无需事先知道它是哪个值，然后返回布尔值，以便我可以根据结果在代码中做不同的事情.

In some of my code I put a series of objects in a list and I build an additional list out of their attributes, which is a string. I need to determine if all the items in this second list have the exact same value, without knowing beforehand which value it is, and return a bool so that I can do different things in my code depending on the result.

我事先不知道属性的名称，这就是为什么我试图使某些属性尽可能通用.

I can't know the names of the properties beforehand, that is why I'm trying to make something as generic as possible.

为使示例更清楚，一个理想的函数"all_same"将像这样工作:

To make the example clear, an ideal function, called "all_same" would work like this:

>>> property_list = ["one", "one", "one"]
>>> all_same(property_list)
True
>>> property_list = ["one", "one", "two"]
>>> all_same(property_list)
False

我当时想列出一个唯一元素，然后检查其长度是否为1，但是我不确定这是否是最优雅的解决方案.

I was thinking of making a list of unique elements and then check if its length is 1, but I'm not sure if it's the most elegant solution out there.

推荐答案

def all_same(items):
    return all(x == items[0] for x in items)

示例:

>>> def all_same(items):
...     return all(x == items[0] for x in items)
...
>>> property_list = ["one", "one", "one"]
>>> all_same(property_list)
True
>>> property_list = ["one", "one", "two"]
>>> all_same(property_list)
False
>>> all_same([])
True

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