在Python中从列表列表中删除重复项 [英] Removing duplicates from list of lists in Python

问题描述

如果想根据每个嵌套列表的第一个元素评估重复项，谁能提出一个好的解决方案从嵌套列表中删除重复项?

Can anyone suggest a good solution to remove duplicates from nested lists if wanting to evaluate duplicates based on first element of each nested list?

主列表如下:

L = [['14', '65', 76], ['2', '5', 6], ['7', '12', 33], ['14', '22', 46]]

如果已经在第一位置[k][0]处存在另一个具有相同元素的列表，那么我想删除该列表并得到以下结果:

If there is another list with the same element at first position [k][0] that had already occurred, then I'd like to remove that list and get this result:

L = [['14', '65', 76], ['2', '5', 6], ['7', '12', 33]]

您能建议一种实现该目标的算法吗?

Can you suggest an algorithm to achieve this goal?

推荐答案

您是否关心保留订单/删除了哪些重复项?如果没有，那么:

Do you care about preserving order / which duplicate is removed? If not, then:

dict((x[0], x) for x in L).values()

会做到的.如果您想保留订单，并想保留第一个订单，则:

will do it. If you want to preserve order, and want to keep the first one you find then:

def unique_items(L):
    found = set()
    for item in L:
        if item[0] not in found:
            yield item
            found.add(item[0])

print list(unique_items(L))

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