SWI-Prolog中的填充列表 [英] Fill list in SWI-Prolog

问题描述

我试图用数字1,2,3，...，N填充给定长度N的列表.

I am trying to fill a list of given length N with numbers 1,2,3,...,N.

我认为这可以通过以下方式完成:

I thought this could be done this way:

create_list(N,L) :-
    length(L,N),
    forall(between(1,N,X), nth1(X,L,X)).

但是，这似乎不起作用.谁能说我做错了吗?

However, this does not seem to work. Can anyone say what I am doing wrong?

推荐答案

如果我理解正确，则内置谓词numlist/3可以. http://www.swi-prolog.org/pldoc/man?predicate = numlist/3

If I understood correctly, the built-in predicate numlist/3 would do. http://www.swi-prolog.org/pldoc/man?predicate=numlist/3

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