如何在Python中的元组列表中对每个元组的第一个值求和? [英] How do I sum the first value in each tuple in a list of tuples in Python?

问题描述

我有一个像这样的元组列表(总是成对出现):

I have a list of tuples (always pairs) like this:

[(0, 1), (2, 3), (5, 7), (2, 1)]

我想找到每对中第一项的总和，即:

I'd like to find the sum of the first items in each pair, i.e.:

0 + 2 + 5 + 2

如何在Python中执行此操作?目前，我正在遍历列表:

How can I do this in Python? At the moment I'm iterating through the list:

sum = 0
for pair in list_of_pairs:
   sum += pair[0]

我觉得必须有一种更Python化的方式.

I have a feeling there must be a more Pythonic way.

推荐答案

与Python 2.3兼容的版本是

A version compatible with Python 2.3 is

sum([pair[0] for pair in list_of_pairs])

或在最新版本的Python中，请参见此答案或

or in recent versions of Python, see this answer or this one.

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