循环遍历2个列表，重复最短直到最长的结尾 [英] Loop over 2 lists, repeating the shortest until end of longest

问题描述

我敢肯定有一个简单而明显的方法可以做到这一点，但是我一直在谷歌搜索并阅读文档，但是我什么都找不到.

I am sure there is an easy and obvious way to do this, but I have been googling and reading the docs and I just cannot find anything.

这是我要实现的目标:

la = ['a1', 'a2', 'a3', 'a4']
lb = ['b1', 'b2']
result = ['a1_b1', 'a2_b2', 'a3_b1', 'a4_b2']

我有一个日期列表，其中一些带有标记.然后，我有一个更大的日期列表，我想将最小的列表尽可能多地放入更大的列表中.可能需要某种循环，因为我需要访问较大列表中的日期才能获得最终结果.

I have a list of dates and some of them have something marked on them. I then have a much larger list of dates and I want to put the smallest list inside the bigger list as many times as possible. It will probably require some sort of loop as I need access to the dates in the larger list for the end result.

由于某种原因，我只是看不到一个好方法.

For some reason, I just cannot see a good way to do this.

推荐答案

尝试

result = ["_".join((i, j)) for i, j in itertools.izip(la, itertools.cycle(lb))]

这篇关于循环遍历2个列表，重复最短直到最长的结尾的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！