Python-将列表范围设置为特定值 [英] Python - set list range to a specific value

问题描述

我需要基于边界为(start,end)的元组将列表的子集设置为特定值.

I need to set a subset of a list to a specific value based on a tuple with bounds (start,end).

目前我正在这样做:

indexes = range(bounds[0], bounds[1] + 1)
for i in indexes:
   my_list[i] = 'foo'

这对我来说似乎不好.还有更Python化的方法吗?

This doesn't seem good to me. Is there a more pythonic approach?

推荐答案

使用切片分配:

my_list[bounds[0]:bounds[1] + 1] = ['foo'] * ((bounds[1] + 1) - bounds[0])

或使用局部变量只添加一次+ 1:

or using local variables to add your + 1 only once:

lower, upper = bounds
upper += 1
my_list[lower:upper] = ['foo'] * (upper - lower)

您可能希望将上限存储为非包含性，以便更好地使用python并避免所有+ 1计数.

You may want to store the upper bound as non-inclusive, to play better with python and avoid all the + 1 counts.

演示:

>>> my_list = range(10)
>>> bounds = (2, 5)
>>> my_list[bounds[0]:bounds[1] + 1] = ['foo'] * ((bounds[1] + 1) - bounds[0])
>>> my_list
[0, 1, 'foo', 'foo', 'foo', 'foo', 6, 7, 8, 9]

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