解雇弹出窗口时，后退按钮是pressed [英] Dismiss Pop up window when back button is pressed

问题描述

我要关闭该弹出窗口时后退按钮是pressed。我试着用这个code：
popwindow.setBackgroundDrawable（新BitmapDrawable（））; 和它的作品。但是，在我的应用程序，弹出应该保持，甚至触摸弹出窗口外后。它应该被解雇，只有当后退按钮是pressed。所以，我想这样的： popwindow.setFocusable（假）;
现在它的时候弹出感动外不是不屑一顾。但它不是驳回背部preSS了。我不想在此改变`onBack pressed（）。是否有任何其他的方式，通过它我可以做到这一点。在此先感谢..

I want to dismiss the pop up window when back button is pressed. I tried with this code: popwindow.setBackgroundDrawable(new BitmapDrawable()); and it works. But in my app, pop should remain, even after touching outside of the pop up window. It should be dismissed only when back button is pressed. So I tried this: popwindow.setFocusable(false); Now its not dismissing when touched outside the pop up. But its not dismissing on back press too. I do not want to overide `onBackPressed(). Is there any other way, through which i can achieve this. Thanks in advance..

推荐答案

要停用弹出解雇点击当外界popwindow的
设置

popwindow.setCanceledOnTouchOutside(false);

和作为驳回的后退按钮
设置

popwindow.setCancelable(true);

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