获取包含子字符串的第一个列表索引? [英] Get first list index containing sub-string?

问题描述

对于列表，方法list.index(x)返回值为x的第一项列表中的索引.但是，如果我要查看列表项而不是整个列表项，该如何最大程度地使用Pythoninc方法?

For lists, the method list.index(x) returns the index in the list of the first item whose value is x. But if I want to look inside the list items, and not just at the whole items, how do I make the most Pythoninc method for this?

例如，使用

l = ['the cat ate the mouse',
     'the tiger ate the chicken',
     'the horse ate the straw']

此函数将返回带有参数tiger的1.

this function would return 1 provided with the argument tiger.

推荐答案

一种非光滑方法:

def index_containing_substring(the_list, substring):
    for i, s in enumerate(the_list):
        if substring in s:
              return i
    return -1

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