在元组列表列表中拆分元组列表 [英] split list of tuples in lists of list of tuples

问题描述

我有一个类似的元组列表:

I have a list of tuples like:

[(1,a),(2,b), (1, e), (3, b), (2,c), (4,d), (1, b), (0,b), (6, a), (8, e)]

我想将其分成每个"b"的列表列表

I want to split it into list of lists at every "b"

[[(1,a),(2,b)], [(1, e), (3, b)], [(2,c), (4,d), (1, b)], [(0,b)], [(6, a), (8, e)]]

有什么Python方法可以做到这一点吗?

is there any pythonic way to do this?

推荐答案

my_list = [(1, "a"),(2, "b"), (1, "e"), (3, "b"), (2, "c"), (1, "b"), (0, "b")]
result, temp = [], []

for item in my_list:
    temp.append(item)
    if item[1] == 'b':
        result.append(temp)
        temp = []

if len(temp) > 0:
    result.append(temp)

print result
# [[(1, 'a'), (2, 'b')], [(1, 'e'), (3, 'b')], [(2, 'c'), (1, 'b')], [(0, 'b')]]

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