删除双重列表的外部列表 [英] Remove the outer list of a double list

问题描述

假设我有一个包含以下内容的列表:

Let's say i have a list that consist of:

[['a','b','c','d']]

是否有一种简单的方法可以删除外部列表，以便输出为

Is there an easy way to remove the outer list so the output would be

['a','b','c','d']

我想到了pop之类的东西，但是删除了元素，我只想删除外部列表.

I figured something like pop, but that remove the element, and i just want to remove the outer list.

我知道我可以遍历双重列表并将元素添加到新列表中，并且可以解决问题，但我对该解决方案不满意，我希望使用更干净的代码来使之更平滑.

I know i could iterate over the double list and append the elements to a new list, and the problem would be solved, but im not happy with that solution, i want a smoother one with cleaner code.

推荐答案

您可以使用拆包:

[new_list] = [['a','b','c','d']]
print(new_list)

输出:

['a','b','c','d']

这篇关于删除双重列表的外部列表的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！