从列表中删除与子字符串匹配的项目 [英] Removing an item from list matching a substring

问题描述

如果元素与子字符串匹配，如何从列表中将其删除?

How do I remove an element from a list if it matches a substring?

我尝试使用pop()和enumerate方法从列表中删除元素，但似乎我缺少一些需要删除的连续项目:

I have tried removing an element from a list using the pop() and enumerate method but seems like I'm missing a few contiguous items that needs to be removed:

sents = ['@$\tthis sentences needs to be removed', 'this doesnt',
     '@$\tthis sentences also needs to be removed',
     '@$\tthis sentences must be removed', 'this shouldnt',
     '# this needs to be removed', 'this isnt',
     '# this must', 'this musnt']

for i, j in enumerate(sents):
  if j[0:3] == "@$\t":
    sents.pop(i)
    continue
  if j[0] == "#":
    sents.pop(i)

for i in sents:
  print i

输出:

this doesnt
@$  this sentences must be removed
this shouldnt
this isnt
#this should
this musnt

所需的输出:

this doesnt
this shouldnt
this isnt
this musnt

推荐答案

简单的东西怎么样:

>>> [x for x in sents if not x.startswith('@$\t') and not x.startswith('#')]
['this doesnt', 'this shouldnt', 'this isnt', 'this musnt']

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