如何将2元组的列表分成两个列表? [英] How to split a list of 2-tuples into two lists?

问题描述

我有很多2元组的列表. 我想将列表分为两个列表，一个列表由列表中所有元组的第一个元素组成，另一个列表由所有元组的第二个元素组成.我想知道如何有效地做到这一点?谢谢！

I have a list of many 2-tuples. I would like to split the list into two lists, one list consisting of the first elements of all the tuples in the list, and the other list consisting of the second elements of all the tuples. I wonder how to do that efficiently? Thanks!

例如，我有一个列表y:

>>> y = [('ab',1), ('cd', 2), ('ef', 3) ]
>>> type(y)
<type 'list'>

我希望得到两个列表['ab', 'cd', 'ef']和[1, 2, 3].

I hope to get two lists ['ab', 'cd', 'ef'] and [1, 2, 3].

推荐答案

a,b = zip(*y)

是您所需要的...

或者如果您需要它们作为列表而不是元组

or if you need them as lists and not tuples

a,b = map(list,zip(*y))

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