如何从python中的列表中删除重复的元组? [英] How to remove duplicate tuples from a list in python?

问题描述

我有一个包含元组列表的列表，如下所示.

I have a list that contains list of tuples as follows.

mylist = [['xxx', 879], ['yyy', 315], ['xxx', 879], ['zzz', 171], ['yyy', 315]]

我想从mylist中删除重复的元组，并获得如下输出.

I want to remove the duplicate tuples from mylist and get an output as follows.

mylist = [['xxx', 879], ['yyy', 315], ['zzz', 171]]

似乎python中的set不适用于它.

It seems like set in python does not work for it.

mylist = list(set(mylist))

在python中有任何快速简便的方法(也许使用库)吗?

Is there any fast and easy way of doing this in python (perhaps using libraries)?

推荐答案

您需要编写保留第一个子列表的代码，其余部分删除.最简单的方法是反转mylist，将其加载到dict对象，然后再次将其键值对作为列表检索.

You need to write code that keeps the first of the sub-lists, dropping the rest. The simplest way to do this is to reverse mylist, load it into an dict object, and retrieve its key-value pairs as lists again.

>>> list(map(list, dict(mylist).items()))

或者，使用列表理解-

>>> [list(v) for v in dict(mylist).items()]

[['zzz', 171], ['yyy', 315], ['xxx', 879]]

请注意，此答案不维护顺序！另外，如果您的子列表可以包含2个以上的元素，则该方法涉及对数据的郁金香版本进行哈希处理，例如 @JohnJosephFernandez的答案显示，这将是最好的选择.

Note, that this answer does not maintain order! Also, if your sub-lists can have more than 2 elements, an approach involving hashing the tuplized versions of your data, as @JohnJosephFernandez' answer shows, would be the best thing to do.

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