如何在以lst [0] [0]为键的Python中将嵌套列表转换为字典 [英] How to Convert Nested List into dictionary in Python where lst[0][0] is the key

问题描述

我有一个Python 3.x嵌套列表，如下所示:

I have a Python 3.x nested list that looks like the following:

lst = [['kataba', 'V:', '3rd_sg_masc_perf_active'], ['kataba:', 'V:', '3rd_dual_masc_perf_active'], ['katabu:', 'V:', '3rd_pl_masc_perf_active'], ['katabat', 'V:', '3rd_sg_fm_perf_active'], ['katabata:', 'V:', '3rd_dual_fm_perf_active']]

我将切一个实例，以便我的问题更加清楚

I will slice one instance so that my question will be clearer

>>> lst[0]
['kataba', 'V:', '3rd_sg_masc_perf_active']
>>> lst[0][0]
'kataba'
>>> lst[0][1:]
['V:', '3rd_sg_masc_perf_active']

如何将上述嵌套列表转换成字典，例如，lst [0] [0]将是字典键，而lst [0] [1:]将是键的值.

How to convert the above nested list into a dictionary where, for example, lst[0][0] will be the dictionary key, and lst[0][1:] will be the value of the key.

此嵌套列表包含数以万计的元素.

This nested list contains tens of thousands of elements.

您能帮我吗，因为我尝试了很多选择，但似乎我没有这样做的逻辑.

Could you help me, because I have tried many options but it seems that I don't have the logic to do it.

推荐答案

如果我对您的理解正确，那么我认为您是在遵循以下条件.

If I understand you correctly, I think you're after the following.

对于2.7+版本，您可以使用dict-comp:

You can use a dict-comp for versions 2.7+:

{ k[0]: k[1:] for k in lst }

在2.7(2.6及以下版本)之前，这可以使用内置的dict完成，例如:

Prior to 2.7 (2.6 and below), this would have been done using the dict builtin, eg:

dict( (k[0], k[1:]) for k in lst)
# {'kataba': ['V:', '3rd_sg_masc_perf_active'], 'katabat': ['V:', '3rd_sg_fm_perf_active'], 'katabata:': ['V:', '3rd_dual_fm_perf_active'], 'katabu:': ['V:', '3rd_pl_masc_perf_active'], 'kataba:': ['V:', '3rd_dual_masc_perf_active']}

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