基于最后一个元素的Python元组排序 [英] Python tuples sorting based on last element
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问题描述
这是我的问题,我有tuple1=[(1, 3), (3, 2), (2, 1)]
我想根据每个元组的最后一位对元组进行排序,因此结果看起来像这样
output=[(2, 1), (3, 2), (1, 3)]
以下是我的代码
Here is my question i have tuple1=[(1, 3), (3, 2), (2, 1)]
i want to sort tuple based on last digit of each tuple so the resultant will look like this
output=[(2, 1), (3, 2), (1, 3)]
below is my code
i=0
for x in tuples:
c.append(x[len(x)-1])
last=sorted(c)
for y in last.iteritems():
if(y in x[len(x)-1]):
print x
#b.insert(i,x)
i=i+1
运行iam后收到错误消息
after running iam getting an error message
Traceback (most recent call last):
File "x.py", line 47, in <module>
sort_last([(1, 3), (3, 2), (2, 1)])
File "x.py", line 35, in sort_last
if(y in x[len(x)-1]):
TypeError: argument of type 'int' is not iterable
推荐答案
在sorted
函数中指定key
参数.
>>> tuple1=[(1, 3), (3, 2), (2, 1)]
>>> output = sorted(tuple1, key=lambda x: x[-1])
>>> print output
[(2, 1), (3, 2), (1, 3)]
sorted
函数(以及list.sort
方法)具有一个可选的key
参数,该参数指定要对列表进行排序的内容.
The sorted
function (as well as the list.sort
method) has an optional key
argument which specifies what to sort the list on.
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