邮编为列表理解 [英] Zip as a list comprehension

问题描述

我有一个相当类似的数据列表:

I have a fairly last list of data like this:

data = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

我正在尝试将其压缩，以便得到如下内容:

I'm trying to zip it so that that I get something like this:

zipped_data = [(1, 4, 7), (2, 5, 8), (3, 6, 9)]

我知道我可以做到

l = [(data[0]), (data[1]), (data[2])]
zipped_data = zip(*l)

但是我想编写一个列表理解来对data中的任何数量的项目执行此操作.我试过了，但是没有用.

But I would like to write a list comprehension to do that for any number of items in data. I tried this, but it didn't work.

s = [zip(i) for i in data]
s
[[(1,), (2,), (3,)], [(4,), (5,), (6,)], [(7,), (8,), (9,)]]

任何人都可以识别出我在哪里出问题了吗?谢谢.

Can anyone identify where I've gone wrong here? Thanks.

推荐答案

尝试使用*:

In [2]: lis=[[1, 2, 3], [4, 5, 6], [7, 8, 9]]

In [3]: zip(*lis)
Out[3]: [(1, 4, 7), (2, 5, 8), (3, 6, 9)]

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