Android的HTTP POST + Web服务PHP [英] Android http post + web service PHP
本文介绍了Android的HTTP POST + Web服务PHP的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在PHP返回一个字符串的Web服务，他收到
2参数应用，身份证和Te。
我测试过它与mozzila插件使用的海报，所以我决定用它为我的Android应用。
这是我的Android code：
最后的查询字符串= NULL;AsyncHttpClient客户端=新AsyncHttpClient（）;
RequestParams RP =新RequestParams（）;
rp.put（ID，NUM）;
rp.put（TE，标签）;
Log.i（HTTP，送之前\\ n）;
client.post（http://appdomain.hol.es/webService.php，RP，新JsonHtt presponseHandler（）{ 公共无效的onSuccess（字符串jObject）
{
query.replace（查询，jObject）;
Log.i（HTTP，recived：+ jObject +\\ n）; }
公共无效onFailure处（Throwable的为arg0）
{
Log.i（HTTP，失败）;
}
}）;
我调试蒙山log.i，我已经可以看到，它并不显示既不recived没有失败。
任何人都可以helpl我？
PD：我留下最相关的WebService
的$ id = $ _ POST [ID];
$ TE = $ _ POST [TE];
$查询=SELECT`preg`，`respA`，`respB`，`respC`，`respD`，``respV`FROM$忒`其中`id` =$ ID。;$ resultado =的mysql_query（$查询，$链接）;
$ arraySalida =阵列（）;
而（$ registro = mysql_fetch_assoc（$ resultado））：
$卡德纳= \"{$registro['$p$pg']};{$registro['respA']};{$registro['respB']};{$registro['respC']};{$registro['respD']};{$registro['respV']}\";
$ arraySalida [] = $卡德纳;ENDWHILE;
回声破灭（：，$ arraySalida）;
@jaimin作品的解决办法，但编译器说：类型不匹配：不能从AsyncTask的转换为字符串在
（！）这是code：
公共字符串BBDD（INT NUM，串片）
{
HttpAsyncTask httpAsyncTask =新HttpAsyncTask（将String.valueOf（NUM）选项卡）;
（！）/ * * /字符串resul = httpAsyncTask.execute（http://opofire.hol.es/webServiceOpoFire.php）; 返回resul;
}
解决方案
有关HTTP POST我会建议你使用的AsyncTask＆LT;>将在用户界面上单独的线程中运行
这里是code两个月以来我使用和它的做工精细
私有类HttpAsyncTask扩展的AsyncTask＆LT;弦乐，太虚，字符串＆GT; {
私人字符串ID，忒;
公共HttpAsyncTask（ID字符串，字符串TE）{
this.id = ID;
this.te = TE; } @覆盖
保护字符串doInBackground（字符串的URL ...）{ 返回POST（网址[0]）;
}
// onPostExecute显示的AsyncTask的结果。
@覆盖
保护无效onPostExecute（字符串结果）{
Toast.makeText（getBaseContext（），发送的数据！，Toast.LENGTH_LONG）.show（）;
}
}
公共静态字符串POST（字符串URL）{
为InputStream的InputStream = NULL;
字符串结果=;
尝试{ // 1.创建HttpClient的
HttpClient的HttpClient的=新DefaultHttpClient（）; // 2.化妆POST请求到指定的URL
HttpPost httpPost =新HttpPost（URL）;
以这种方式//传递参数 清单＆LT;＆的NameValuePair GT; namevaluepairs中=新的ArrayList＆LT;＆的NameValuePair GT;（2）;
nameValuePairs.add（新BasicNameValuePair（ID，价值））;
nameValuePairs.add（新BasicNameValuePair（TE，价值））; //添加数据
httppost.setEntity（新UrlEn codedFormEntity（namevaluepairs中））; // 8.执行POST请求到指定的URL
HTT presponse HTT presponse = httpclient.execute（httpPost）; // 9.收到响应为InputStream的
的InputStream = HTT presponse.getEntity（）的getContent（）。 // 10.转换的InputStream串
如果（的InputStream！= NULL）
结果= convertInputStreamToString（InputStream的）;
其他
结果=没有工作！ }赶上（例外五）{
Log.d（InputStream的，e.getLocalizedMessage（））;
}
// 11返回结果
返回结果;}私人静态字符串convertInputStreamToString（的InputStream的InputStream）抛出IOException
// TODO自动生成方法存根 的BufferedReader的BufferedReader =新的BufferedReader（新的InputStreamReader（InputStream的））;
串线=;
字符串结果=;
而（（行= bufferedReader.readLine（））！= NULL）
结果+ =行; inputStream.close（）;
返回结果;}
传递值，您可以创建构造这样。
形成你的活动做到这一点。
HttpAsyncTask httpAsyncTask =新HttpAsyncTask（ID，TE）; //这会传递变量的值
字符串ResultfromServer = httpAsyncTask.execute（urlStr）; //字符串ResultfromServer是你的响应字符串
和中的AsyncTask我已经创建构造
这是非常有帮助，我希望它会帮助你太
I have a web service in PHP which returns a String, he recives two parametres, id and te. I've tested its using with the mozzila addon poster, so i decided to use it for my android app.
This is my android code:
final String query = null;
AsyncHttpClient client = new AsyncHttpClient();
RequestParams rp = new RequestParams();
rp.put("id", num);
rp.put("te", tab);
Log.i("http","before send\n");
client.post("http://appdomain.hol.es/webService.php",rp, new JsonHttpResponseHandler(){
public void onSuccess(String jObject)
{
query.replace(query, jObject);
Log.i("http","recived: "+jObject+"\n");
}
public void onFailure(Throwable arg0)
{
Log.i("http","fail");
}
});
I'm debugging whith log.i and i've could seen that it doesn't show neither recived neither fail. can anyone helpl me?
PD: i leave the most relevant of webService
$id = $_POST["id"];
$te = $_POST["te"];
$query = "SELECT `preg` , `respA` , `respB` , `respC` , `respD` , `respV`FROM `".$te."` WHERE `id` =".$id;
$resultado= mysql_query($query,$link);
$arraySalida = array();
while($registro = mysql_fetch_assoc ($resultado) ):
$cadena = "{$registro['preg']};{$registro['respA']};{$registro['respB']};{$registro['respC']};{$registro['respD']};{$registro['respV']}";
$arraySalida[]= $cadena;
endwhile;
echo implode(":",$arraySalida);
the solution of @jaimin works but the compiler says: Type mismatch: cannot convert from AsyncTask to String in (!)
this is the code:
public String BBDD(int num, String tab)
{
HttpAsyncTask httpAsyncTask = new HttpAsyncTask(String.valueOf(num),tab);
/*(!)*/String resul = httpAsyncTask.execute("http://opofire.hol.es/webServiceOpoFire.php");
return resul;
}
解决方案
for Http Post i'll suggest you to use AsyncTask<> which will run in separate thread from UI here is the code i am using since two months and its working fine
private class HttpAsyncTask extends AsyncTask<String, Void, String> {
private String id,te;
public HttpAsyncTask(String id,String te){
this.id = id;
this.te = te;
}
@Override
protected String doInBackground(String... urls) {
return POST(urls[0]);
}
// onPostExecute displays the results of the AsyncTask.
@Override
protected void onPostExecute(String result) {
Toast.makeText(getBaseContext(), "Data Sent!", Toast.LENGTH_LONG).show();
}
}
public static String POST(String url){
InputStream inputStream = null;
String result = "";
try {
// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(url);
// pass parameters in this way
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "value "));
nameValuePairs.add(new BasicNameValuePair("te", "value"));
//add data
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// 8. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
// 9. receive response as inputStream
inputStream = httpResponse.getEntity().getContent();
// 10. convert inputstream to string
if(inputStream != null)
result = convertInputStreamToString(inputStream);
else
result = "Did not work!";
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}
// 11. return result
return result;
}
private static String convertInputStreamToString(InputStream inputStream) throws IOException {
// TODO Auto-generated method stub
BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(inputStream));
String line = "";
String result = "";
while((line = bufferedReader.readLine()) != null)
result += line;
inputStream.close();
return result;
}
for passing values you can create constructor like this.
form your activity do this
HttpAsyncTask httpAsyncTask = new HttpAsyncTask(id,te);//this will pass variables values
String ResultfromServer = httpAsyncTask.execute(urlStr);// String ResultfromServer is your response string
and in AsyncTask I've created constructor
this is very helpful for me hope it will help you too
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