python中的排序列表 [英] sorting list in python

问题描述

如果我有字符串列表，例如["a143.txt", "a9.txt", ]如何按列表中的数字而不是字符串按升序对其进行排序. IE.自9 < 143以来，我希望"a9.txt"出现在"a143.txt"之前.

if I have a list of strings e.g. ["a143.txt", "a9.txt", ] how can I sort it in ascending order by the numbers in the list, rather than by the string. I.e. I want "a9.txt" to appear before "a143.txt" since 9 < 143.

谢谢.

推荐答案

它称为自然排序顺序"， 来自 http://www.codinghorror.com/blog/2007 /12/sorting-for-humans-natural-sort-order.html

It's called "natural sort order", From http://www.codinghorror.com/blog/2007/12/sorting-for-humans-natural-sort-order.html

尝试一下:

import re 

def sort_nicely( l ): 
  """ Sort the given list in the way that humans expect. 
  """ 
  convert = lambda text: int(text) if text.isdigit() else text 
  alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)', key) ] 
  l.sort( key=alphanum_key ) 

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