在python中平均分配列表 [英] Equally distribute a list in python

问题描述

假设我在python中有以下列表:

Suppose I have the following list in python:

a = ['a','b','c','d','e','f','g','h','i','j']

我如何分配这样的列表:

How do I distribute the list like this:

['a','f']
['b','g']
['c','h']
['d','i']
['e','j']

如果我有一个长度不等的列表并将多余的"项目放在一个单独的列表中，该如何实现?

And how do I achieve this if I have a list of unequal length and putting the 'superfluous' items into a separate list?

我希望能够以指示的方式将原始列表的元素分发到 n 个部分.

I want to be able to distribute the elements of the original list into n parts in the indicated manner.

因此，如果n = 3，那将是:

So if n=3 that would be:

['a','d','g']
['b','e','h']
['c','f','i']

和单独列表中的多余"元素

and the 'superfluous' element in a separate list

['j']

推荐答案

您可以使用> c0> 并具有列表理解功能:

You can use zip with a list comprehension:

def distribute(seq):
    n = len(seq)//2  #Will work in both Python 2 and 3
    return [list(x) for x in zip(seq[:n], seq[n:])]

print distribute(['a','b','c','d','e','f','g','h','i','j'])
#[['a', 'f'], ['b', 'g'], ['c', 'h'], ['d', 'i'], ['e', 'j']]

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