如何以不区分大小写的方式从列表中删除单词? [英] How do I remove words from a List in a case-insensitive manner?

问题描述

我有一个名为words的列表，其中包含大写或小写的单词，或它们的某种组合.然后，我有另一个名为stopwords的列表，其中仅包含小写单词.现在，我想遍历stopwords中的每个单词，并以不区分大小写的方式从words中删除该单词的所有实例，但是我不知道该怎么做.有建议吗?

I have a list called words containing words which may be in upper or lower case, or some combination of them. Then I have another list called stopwords which contains only lowercase words. Now I want to go through each word in stopwords and remove all instances of that word from words in a case-insensitive manner, but I don't know how to do this. Suggestions?

示例:

words = ['This', 'is', 'a', 'test', 'string']
stopwords = ['this', 'test']

for stopword in stopwords:
    if stopword in words:
        words.remove(stopword);

print words

显示的结果是这样的:['This', 'is', 'a', 'string']

The result shown is this: ['This', 'is', 'a', 'string']

正确的回报应该是这样的:['is', 'a', 'string']

The correct return should have been this: ['is', 'a', 'string']

推荐答案

将您的单词小写，这样您就不必担心大小写了:

Make your word lowercase so you don't need to worry about casing:

words = ['This', 'is', 'a', 'test', 'string']
stopwords = {'this', 'test'}

print([i for i in words if i.lower() not in stopwords])

输出:

['is', 'a', 'string']

作为附加说明，每条@ cricket_007(并感谢@chepner进行了更正)注释，将停用词设置为一组将使其更具性能.注意上面对停用词的更改，使其成为一个集合而不是一个列表.

As an additional note, per @cricket_007 (and thanks to @chepner for the correction) comment, making stopwords a set would make it more performant. Notice the change to stopwords above making it a set instead of a list.

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