在Python中的列表内压缩列表 [英] Zipping lists within a list in Python

问题描述

我有一个列表列表

big_list = [['a1','b1','c1'], ['a2','b2','c3'], ['a3','b3','c3']]

如何在列表中压缩列表?

how do I zip the lists within this list?

我想做的是zip(list1,list2,list3)，但是要动态地做

what I want to do is zip(list1,list2,list3), but do this dynamically

我认为它必须与我不熟悉的args和kwargs有关，欢迎任何解释

I believe it has to do smth with args and kwargs which I am not familiar with, any explanation is welcome

谢谢

推荐答案

使用*args参数扩展语法:

zip(*big_list)

*(闪屏)告诉Python将每个元素都以可迭代方式接受，并将其作为单独的参数应用于函数.

The * (splash) tells Python to take each element in an iterable and apply it as a separate argument to the function.

演示:

>>> big_list = [['a1','b1','c1'], ['a2','b2','c3'], ['a3','b3','c3']]
>>> zip(*big_list)
[('a1', 'a2', 'a3'), ('b1', 'b2', 'b3'), ('c1', 'c3', 'c3')]

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