Python家庭作业-创建新列表 [英] Python Homework - creating a new list

问题描述

作业:

编写一个名为splitList(myList, option)的函数，该函数将一个列表和一个选项(输入值为0或1)作为输入.如果option的值为0，则该函数返回一个列表，该列表由myList中的元素组成，为负数，并且如果该选项的值为1，则该函数返回一个列表，该列表由myList中偶数个元素组成.

Write a function called splitList(myList, option) that takes, as input, a list and an option, which is either 0 or 1. If the value of the option is 0, the function returns a list consisting of the elements in myList that are negative, and if the value of the option is 1, the function returns a list consisting of the elements in myList that are even.

我知道如何确定数字是否为偶数以及数字是否为负数.我正在努力寻找如何基于选项"返回新的负数或偶数列表

I know how to determine if a number is even and if a number is negative. I'm struggling with how to return a new list of negative or even numbers based on "option"

这是我到目前为止所得到的:

This is what I've gotten so far:

def splitList(myList):
    newlist = []
    for i in range(len(myList)):
        if (myList[i]%2 == 0):
           newlist.append(myList [i])
    return newlist

该程序出现以下错误:

Traceback (most recent call last): File "<string>", line 1, in <fragment> 
builtins.TypeError: splitList() takes exactly 1 positional argument (4 given)

推荐答案

正如我在我的评论中提到的，您应该对缩进进行标准化:Python标准是四个空格.通常，您可以将编辑器设置为插入四个空格而不是制表符(也不希望将制表符与空格混用).

As I mentioned in my comment, you should standardize your indentation: four spaces is Python standard. You can usually set your editor to insert four spaces instead of tabs (don't want to mix tabs with spaces, either).

关于您的实际问题:尝试编写总共三个函数:一个返回所有负值，一个返回偶数，另一个基于option调用适当的函数.

As to your actual question: try writing three total functions: one that returns all the negative values, one that returns even values, and one that calls the appropriate function based on option.

def splitlist(myList, option):
    if option == 1:
        return get_even_elements(myList)
    elif option == 0:
        return get_negative_elements(myList)

def get_even_elements(myList):
    pass # Implementation this method here.

def get_negative_elements(myList):
    pass # Implementation this method here.

# Test it out!
alist = [-1, 2, -8, 5]
print splitlist(alist, 0)
print splitlist(alist, 1)

这篇关于Python家庭作业-创建新列表的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！