Python，二维列表和坐标 [英] Python, two dimensional list and coordinates

问题描述

我有一个二维列表:

def list():
    list1 =[1,2,3,4,5]
    list2 =[0,0,0,0,0]
    list3 =[6,7,8,9,10]

    list=[list1,list2,list3]

    for i in list:
        print(i)

list()

6将具有坐标(0,2)，对吗? 我想将6移到(0,1)，当我这样做时，我也想将(0,2)变成0.

6 will have the coordinates (0,2), right?? I want to move 6 to (0,1) and when I do that, I also want (0,2) to become 0.

我该怎么做?我不知道..我是一个初学者.

How do I do that? I have no idea.. I'm a beginner at this.

推荐答案

只需直接分配给这两个索引对，即从外部列表到内部索引(最后一个列表是2，中间列表是1 )，因此最后一个列表的第一个元素位于[2][0]:

Just assign directly to those two index pairs, indexing from the outer list to the inner (the last list is 2, the middle list is 1), so the first element of the last list is at [2][0]:

outerlist[1][0], outerlist[2][0] = outerlist[2][0], 0

这会将两个值(一个取自outerlist[0][2]，另一个取自文本​​0整数)分配给嵌套列表中的两个位置.

This assigns two values (one taken from outerlist[0][2], the other the literal 0 integer) to the two positions in the nested lists.

如果您想交换这两个位置(从outerlist[0][1]中获取0)，请使用相同的语法:

If you wanted to swap those two positions (taking the 0 from outerlist[0][1]), then do so with the same syntax:

outerlist[1][0], outerlist[2][0] = outerlist[2][0], outerlist[1][0]

因为在将两个值分配给左侧目标之前先评估了右侧表达式:

because the right-hand side expression is evaluated before assigning the two values to the left-hand side targets:

>>> outerlist = [[1, 2, 3, 4, 5], [0, 0, 0, 0, 0], [6, 7, 8, 9, 10]]
>>> outerlist
[[1, 2, 3, 4, 5], [0, 0, 0, 0, 0], [6, 7, 8, 9, 10]]
>>> outerlist[1][0], outerlist[2][0] = outerlist[2][0], outerlist[1][0]
>>> outerlist
[[1, 2, 3, 4, 5], [6, 0, 0, 0, 0], [0, 7, 8, 9, 10]]

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