为什么一个列表中的更改会影响其他列表? [英] Why change in one list affect other list?

问题描述

我有两个列表集合.

List<list<int>> FS = new List<List<int>>();List<List<int> V= new List<List<int>>()

我在FS

现在我的FS外观

FS={{1},{2},{3}}

然后我将FS的值分配给V V = FS 现在我要遍历每对

Then i assigned valus of FS to V V = FS Now i want to go through each pair

//Performing some Logic 
for (int i = 0; i < FS.Count-1; i++)
        {
            for (int k = i + 1; k < FS.Count; k++)
            {
                List<int> temp = new List<int>();
                temp.AddRange(FS[i]);
                temp.AddRange(FS[k]);
                VF.Add(IP_CFFM(temp));
                V.Add(temp);
                if (IP_CFFM(temp) > IP_CFFM(FS[i]) && IP_CFFM(temp) > IP_CFFM(FS[k]))
                {
                   FS[i].AddRange(FS[k]);
                   FS.Remove(FS[k]);

                }
            }
        }

在执行if(condition) V之前看起来像V = {{1},{2},{3},{1,2}} 但是在执行了FS[i].AddRange(FS[k]);行之后，列表V发生了变化，看起来像{{1,2},{2},{3},{1,2}}在if(condition)内一样，我没有在V上进行任何操作或执行任何操作.那为什么会发生呢?

Before executing if(condition) V will Look Like V = {{1},{2},{3},{1,2}} But after executing the line FS[i].AddRange(FS[k]); List V is changed and it look like {{1,2},{2},{3},{1,2}} Within the if(condition), i am not manipulation or not performing anything on V. Then why it happens?

推荐答案

List<T>是一个类，因此是参考.

List<T> is a class, so it is reference.

V = FS实际上是指两个都指向相同的位置/地址空间.

V = FS actually mean both pointing to same location/address space.

这意味着您对它所做的任何事情都会反映在另一个方面.只是您的List

This means that anything you do to it will be reflected in the other. It is just that two different names for your List

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