在python中制作一个在一定范围内的等距数字列表 [英] Making a list of evenly spaced numbers in a certain range in python

问题描述

制作任意长度的列表的Python方法是什么，该列表包含给定范围之间的均匀间隔的数字(而不仅仅是整数)?例如:

What is a pythonic way of making list of arbitrary length containing evenly spaced numbers (not just whole integers) between given bounds? For instance:

my_func(0,5,10) # ( lower_bound , upper_bound , length )
# [ 0, 0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5 ] 

请注意，Range()函数仅处理整数.而这个:

Note the Range() function only deals with integers. And this:

def my_func(low,up,leng):
    list = []
    step = (up - low) / float(leng)
    for i in range(leng):
        list.append(low)
        low = low + step
    return list

似乎太复杂了.有什么想法吗?

seems too complicated. Any ideas?

推荐答案

给出numpy，您可以使用

Given numpy, you could use linspace:

包括正确的端点(5):

Including the right endpoint (5):

In [46]: import numpy as np
In [47]: np.linspace(0,5,10)
Out[47]: 
array([ 0.        ,  0.55555556,  1.11111111,  1.66666667,  2.22222222,
        2.77777778,  3.33333333,  3.88888889,  4.44444444,  5.        ])

不包括正确的端点:

In [48]: np.linspace(0,5,10,endpoint=False)
Out[48]: array([ 0. ,  0.5,  1. ,  1.5,  2. ,  2.5,  3. ,  3.5,  4. ,  4.5])

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