Python检查列表是否嵌套 [英] Python check if a list is nested or not

问题描述

我有一个列表，有时是嵌套的，有时不是.根据是否嵌套，延续是不同的.如何检查此列表是否嵌套?应该输出True或False.

示例:

[1,2,3]-> False

[[1],[2],[3]]-> True

解决方案

您可以使用 isinstance 和生成器表达式与 解决方案

You can use isinstance and a generator expression combined with any. This will check for instances of a list object within your original, outer list.

In [11]: a = [1, 2, 3]

In [12]: b = [[1], [2], [3]]

In [13]: any(isinstance(i, list) for i in a)
Out[13]: False

In [14]: any(isinstance(i, list) for i in b)
Out[14]: True

Note that any will return True as soon as it reaches an element that is valid (in this case if the element is a list) so you don't end up iterating over the whole outer list unnecessarily.

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