分析带有间隔的整数集的字符串以列出 [英] parse string of integer sets with intervals to list

问题描述

我有"2,5,7-9,12"字符串.

我想从中获取[2、5、7、8、9、12]列表.

I want to get [2, 5, 7, 8, 9, 12] list from it.

在python中是否有内置函数?

Is there any built-in function for it in python?

谢谢.

UPD..我想，直接的答案是否.无论如何，感谢您的摘录".由 Sven Marnach 建议.

UPD. I suppose, the straight answer is No. Anyway, thanks for your "snippets". Using one, suggested by Sven Marnach.

推荐答案

此版本处理任意空格，重叠范围，无序范围和负整数:

This version handles arbitrary whitespace, overlapping ranges, out-of-order ranges, and negative integers:

from itertools import chain

def group_to_range(group):
  group = ''.join(group.split())
  sign, g = ('-', group[1:]) if group.startswith('-') else ('', group)
  r = g.split('-', 1)
  r[0] = sign + r[0]
  r = sorted(int(__) for __ in r)
  return range(r[0], 1 + r[-1])

def rangeexpand(txt):
  ranges = chain.from_iterable(group_to_range(__) for __ in txt.split(','))
  return sorted(set(ranges))


>>> rangeexpand('-6,-3--1,3-5,7-11,14,15,17-20')
[-6, -3, -2, -1, 3, 4, 5, 7, 8, 9, 10, 11, 14, 15, 17, 18, 19, 20]
>>> rangeexpand('1-4,6,3-2, 11, 8 - 12,5,14-14')
[1, 2, 3, 4, 5, 6, 8, 9, 10, 11, 12, 14]

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