通过结束字符来分割句子 [英] Splitting a sentence by ending characters

问题描述

最近的一个项目需要我将传入的短语(作为字符串)拆分为它们的组成句子.例如，此字符串:

A recent project has me needing to split incoming phrases (as strings) into their component sentences. For instance, this string:

"Your mother was a hamster, and your father smelt of elderberries! Now go away, or I shall taunt you a second time. You know what, never mind. This entire sentence is far too silly. Wouldn't you agree? I think it is."

需要将其转换为由以下元素组成的列表:

Would need to be turned into a list composed of the following elements:

["Your mother was a hamster, and your father smelt of elderberries",
"Now go away, or I shall taunt you a second time",
"You know what, never mind",
"This entire sentence is far too silly",
"Wouldn't you agree",
"I think it is"]

就此功能而言，句子"是以!，?或.结尾的字符串.请注意，如上所示，应从输出中删除标点符号.

For the purposes of this function, a "sentence" is a string terminated by !, ?, or . Note that punctuation should be removed from the output as shown above.

我有一个工作版本，但是它很丑陋，在开头和结尾留有空格，我不禁想到有更好的方法:

I've got a working version, but it's quite ugly, leaves leading and trailing spaces, and I can't help but think there's a better way:

from functools import reduce

def split_sentences(st):
  if type(st) is not str:
    raise TypeError("Cannot split non-strings")
  sl = st.split('.')
  sl = [s.split('?') for s in sl]
  sl = reduce(lambda x, y: x+y, sl) #Flatten the list
  sl = [s.split('!') for s in sl]
  return reduce(lambda x, y: x+y, sl)

推荐答案

使用re.split代替，可以指定与任何句子结尾字符(以及以下任何空格)匹配的正则表达式.

Use re.split instead to specify a regular expression matching any sentence-ending character (and any following whitespace).

def split_sentences(st):
    sentences = re.split(r'[.?!]\s*', st)
    if sentences[-1]:
        return sentences
    else:
        return sentences[:-1]

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