给定时间段的每月第一天的Python列表 [英] Python list of first day of month for given period

问题描述

我正在尝试找到一种有效的方法来创建日期列表，该日期列表仅包括给定时间段的月份的第一天.像这样但更好的东西:

I am trying find an efficient way of creating a list of dates only including the first day of the month for a given period. Something like this but better:

import datetime
dates = [
  datetime.date (2014, 4, 1),
  datetime.date (2014, 5, 1),
  datetime.date (2014, 6, 1),
  datetime.date (2014, 7, 1),
  datetime.date (2014, 8, 1),
  datetime.date (2014, 9, 1),
  datetime.date (2014, 10, 1),
  datetime.date (2014, 11, 1),
  datetime.date (2014, 12, 1),
  datetime.date (2015, 1, 1),
  datetime.date (2015, 2, 1)]

或者，就此向Google提供了一些指导.干杯！

Alternatively, some direction on what to Google for this. Cheers!

推荐答案

>>> startyear = 2014
>>> startmonth = 4
>>> endyear = 2015
>>> endmonth = 2
>>> [datetime.date(m/12, m%12+1, 1) for m in xrange(startyear*12+startmonth-1, endyear*12+endmonth)]
[datetime.date(2014, 4, 1), datetime.date(2014, 5, 1), datetime.date(2014, 6, 1), datetime.date(2014, 7, 1), datetime.date(2014, 8, 1), datetime.date(2014, 9, 1), datetime.date(2014, 10, 1), datetime.date(2014, 11, 1), datetime.date(2014, 12, 1), datetime.date(2015, 1, 1), datetime.date(2015, 2, 1)]

对于Python 3，您需要使用range而不是xrange和//(

For Python 3, you'll need to use range instead of xrange, and // (floor division) instead of / (which does float division in Python 3):

[datetime.date(m//12, m%12+1, 1) for m in range(startyear*12+startmonth-1, endyear*12+endmonth)]

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