如何在Python中创建多个(但单独的)空列表? [英] How to create multiple (but individual) empty lists in Python?
问题描述
我编写了一个脚本,该脚本在某一时刻生成一堆空列表,并应用具有以下结构的代码:
I wrote a script that at one point generates a bunch of empty lists applying a code with the structure:
A,B,C,D=[],[],[],[]
产生输出:
A=[]
B=[]
C=[]
D=[]
现在是这样,每次使用不同的数据集作为输入时,我都必须手动修改字母.我希望能够实现自动化. 我考虑过这样做:
The way it is right now, I have to manually modify the letters each time I use a different dataset as an input. I want to be able to automatize that. I thought about doing this:
FieldList=[A,B,C,D]
bracket=[]
[[0]for field in FieldList]
for field in FieldList:
bracket=bracket+["[]"]
FieldList=bracket
在这里,我试图复制"A,B,C,D = [],[],[],[]",但显然不是这样.
Here I was trying to replicate " A,B,C,D=[],[],[],[]", but evidently that's not how it works.
我也尝试过:
FieldList=[A,B,C,D]
bracket=[]
[[0]for field in FieldList]
for field in FieldList:
field=[]
但是最后,它只产生一个列表调用"field".
But at the end it just produces a single list call "field".
所以,这就是我需要的列表.我将从csv中读取信息,并将从每一行提取的数据添加到列表中.如果生成列表列表",我是否仍可以分别调用每个列表以将内容附加到列表上?
So, this is what I need the lists for. I will be reading information from a csv and adding the data I'm extracting from each row to the lists. If generate a "list of lists", can I still call each of them individually to append stuff to them?
A,B,C,D=[],[],[],[]
with open(csvPath+TheFile, 'rb') as csvfile: #Open the csv table
r = csv.reader(csvfile, delimiter=';') #Create an iterator with all the rows of the csv file, indicating the delimiter between columns
for i,row in enumerate(r): #For each row in the csv
if i > 0: #Skip header
A.append(float(row[0])) #Extract the information and append it to each corresponding list
B.append(float(row[1]))
C.append(format(row[2]))
D.append(format(row[3]))
推荐答案
您正在使事情变得过于复杂.只需使用列表或字典即可:
You are overcomplicating things. Just use a list or dictionary:
fields = {key: [] for key in 'ABCD'}
然后根据需要引用fields['A']
等,或遍历结构以依次处理每个对象.
then refer to fields['A']
, etc. as needed, or loop over the structure to process each in turn.
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