将列表的每个元素转换为元组 [英] Converting each element of a list to tuple

问题描述

我将列表的每个元素转换为元组，如下所示:

I to convert each element of list to tuple like following :

l = ['abc','xyz','test']

转换为元组列表:

newl = [('abc',),('xyz',),('test',)]

实际上，我用这样的键来字典，因此出于搜索目的，我需要这些键.

Actually I have dict with keys like this so for searching purpose I need to have these.

推荐答案

您可以使用列表理解:

>>> l = ['abc','xyz','test']
>>> [(x,) for x in l]
[('abc',), ('xyz',), ('test',)]
>>>

---

或者，如果您使用的是Python 2.x，则可以使用 zip :

---

Or, if you are on Python 2.x, you could just use zip:

>>> # Python 2.x interpreter
>>> l = ['abc','xyz','test']
>>> zip(l)
[('abc',), ('xyz',), ('test',)]
>>>

---

但是，以前的解决方案在Python 3.x中不起作用，因为zip现在返回一个zip对象.相反，您需要通过将结果放在 :

---

However, the previous solution will not work in Python 3.x because zip now returns a zip object. Instead, you would need to explicitly make the results a list by placing them in list:

>>> # Python 3.x interpreter
>>> l = ['abc','xyz','test']
>>> zip(l)
<zip object at 0x020A3170>
>>> list(zip(l))
[('abc',), ('xyz',), ('test',)]
>>>

我个人更喜欢列表理解而不是最后一种解决方案.

I personally prefer the list comprehension over this last solution though.

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