如何在Python中对列表进行破烂的分割? [英] How to ragged partition a list in Python?

问题描述

是否有内置的Python函数，例如

Is there a built-in Python function such that with

vals=[1,2,3,4,5]

然后foo(vals,2)给出

[[1,2],[3,4],[5]]

我正在寻找Wolfram语言所赋予的行为

I am looking for the behaviour that Wolfram Language gives with

Partition[Range@5, UpTo@2]

{{1, 2}, {3, 4}, {5}}

推荐答案

这既没有内置在Python语言本身，也没有内置在其标准库中，但是可能是您在功能方面寻求的:

This is built into neither the Python language itself nor its standard library, but might be what you are looking for functionality-wise:

安装第三方库更多itertools (不要与itertools模块( 是Python标准库的一部分)，例如与

Install the third-party-library more-itertools (not to be confused with the itertools module, which is part of the Python standard library), e.g. with

pipenv install 'more-itertools >= 2.4'

然后，您可以使用函数sliced() 它提供:

Then you can use the function sliced() it provides:

from more_itertools import sliced

vals = [1,2,3,4,5]
slices = list(sliced(vals, 2))

print(slices)

结果:

[[1, 2], [3, 4], [5]]

如果迭代器不可切片，则可以使用 chunked()来自同一库，而不是切片.

If the iterable isn't sliceable, you can use chunked() from the same library instead of sliced.

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