错误列表索引必须是整数或切片，而不是str [英] error list indices must be integers or slices, not str

问题描述

根据标题，帮助我解决错误. 我试图根据在'rv'变量中的country_name打印countryCode. country_found是国家列表中具有相同值的数据列表， 然后我尝试检索countryCode，然后出现错误

Based on the title, help me solve the error. i've tried to print the countryCode based on country_name which is in 'rv' variable. country_found is list of data that have the same value on countries list, and then i try to retrieve countryCode and there i got the error

rv = "Indonesia"
country_lower = rv.lower()
countries = {
  "DATA": {
    "data": [{
        "countryId": "26",
        "countryCode": "AU",
        "name": "Australia"
    }, {
        "countryId": "17",
        "countryCode": "ID",
        "name": "Indonesia"
    }]
   }
} 
def take_first(predicate, iterable):
 for element in iterable:
    if predicate(element):
        yield element
        break

country_found = list(
 take_first(
    lambda e: e['name'].lower() == country_lower, 
    countries['DATA']['data']
 )
)

default_country_code = 'US'
country_code = (
  country_found['countryCode'] 
  if country_found 
  else default_country_code
)
print (country_code)

推荐答案

country_found是一个列表，但是您正在尝试通过字符串索引获取项目:

country_found is a list, but you are trying to get an item by a string index:

country_found['countryCode']

您可能打算获得比赛的第一个结果:

You've probably meant to get the first result of a match:

country_code = country_found[0]['countryCode'] if country_found else default_country_code

但是，您实际上是否需要将结果作为列表，如果只使用 next() :

But, do you actually need to have the result as a list, what if you would just use next():

result = take_first(lambda e: e['name'].lower() == country_lower, 
                    countries['DATA']['data'])
try:
    country_code = next(result)['countryCode']
except StopIteration:
    country_code = default_country_code

这篇关于错误列表索引必须是整数或切片，而不是str的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！