使用命名列表重命名列表列表 [英] Rename list of lists using a named list

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本文介绍了使用命名列表重命名列表列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

因此,我正在使用一个包含内部其他列表的列表,其结构如下:

So I'm working with a list that contains other lists inside, with this structure:

library(graph)
library(RBGL)
library(Rgraphviz)

show(tree)

$`SO:0001968`
$`SO:0001968`$`SO:0001622`
$`SO:0001968`$`SO:0001622`$`SO:0001624`
$`SO:0001968`$`SO:0001622`$`SO:0001624`$`SO:0002090`
[1] 1

$`SO:0001968`$`SO:0001622`$`SO:0001623`
$`SO:0001968`$`SO:0001622`$`SO:0001623`$`SO:0002091`
[1] 1

$`SO:0001968`$`SO:0001969`
$`SO:0001968`$`SO:0001969`$`SO:0002090`
[1] 1

$`SO:0001968`$`SO:0001969`$`SO:0002091`
[1] 1


dput(tree)
list(`SO:0001968` = list(`SO:0001622` = list(`SO:0001624` = list(
    `SO:0002090` = 1), `SO:0001623` = list(`SO:0002091` = 1)), 
    `SO:0001969` = list(`SO:0002090` = 1, `SO:0002091` = 1)))

我用于构建列表的数据来自名为g的对象:

The data I use to build the list comes from an object called g:

show(g)

A graphNEL graph with directed edges
Number of Nodes = 7 
Number of Edges = 8 


dput(g)
new("graphNEL",
nodes = c("SO:0001968", "SO:0001969", "SO:0001622", 
"SO:0001623", "SO:0001624", "SO:0002090", "SO:0002091"), edgeL = list(
    `SO:0001968` = list(edges = 3:2), `SO:0001969` = list(edges = 6:7), 
    `SO:0001622` = list(edges = 5:4), `SO:0001623` = list(edges = 7L), 
    `SO:0001624` = list(edges = 6L), `SO:0002090` = list(edges = integer(0)), 
    `SO:0002091` = list(edges = integer(0))), edgeData = new("attrData",

    data = list(`SO:0001968|SO:0001622` = list(weight = 1), `SO:0001968|SO:0001969` = list(
        weight = 1), `SO:0001969|SO:0002090` = list(weight = 1), 
        `SO:0001969|SO:0002091` = list(weight = 1), `SO:0001622|SO:0001624` = list(
            weight = 1), `SO:0001622|SO:0001623` = list(weight = 1), 
        `SO:0001623|SO:0002091` = list(weight = 1), `SO:0001624|SO:0002090` = list(
            weight = 1)), defaults = list(weight = 1)), nodeData = new("attrData",

    data = list(`SO:0001968` = list(label = "coding_transcript_variant"), 
        `SO:0001969` = list(label = "coding_transcript_intron_variant"), 
        `SO:0001622` = list(label = "UTR_variant"), `SO:0001623` = list(
            label = "5_prime_UTR_variant"), `SO:0001624` = list(
            label = "3_prime_UTR_variant"), `SO:0002090` = list(
            label = "3_prime_UTR_intron_variant"), `SO:0002091` = list(
            label = "5_prime_UTR_intron_variant")), defaults = list(
        label = NA_character_)), renderInfo = new("renderInfo",

    nodes = list(), edges = list(), graph = list(), pars = list()), 
    graphData = list(edgemode = "directed"))

每个SO:000XXX都对应一个名称,我可以使用函数nodeData查找名称,该函数返回一个命名列表:

Each SO:000XXX corresponds to a name, and I can find the names using the function nodeData, that returns a named list:

nodeData(g, nodes(g), "label")

$`SO:0001968`
[1] "coding_transcript_variant"

$`SO:0001969`
[1] "coding_transcript_intron_variant"

$`SO:0001622`
[1] "UTR_variant"

$`SO:0001623`
[1] "5_prime_UTR_variant"

$`SO:0001624`
[1] "3_prime_UTR_variant"

$`SO:0002090`
[1] "3_prime_UTR_intron_variant"

$`SO:0002091`
[1] "5_prime_UTR_intron_variant"

我需要用nodeData函数的相应字符串替换(或重命名)tree列表中的数据.

What I need is to replace (or rename) the data in the tree list with the corresponding string of the nodeData function.

例如,用nodeData函数将tree列表中的'SO:0001968'替换为coding_transcript_variant.

For example, replace the 'SO:0001968' in the tree list for coding_transcript_variant from the nodeData function.

推荐答案

此递归函数应该可以解决问题:

This recursive function should do the trick :

# you will do this but I couldn't install your packages
# nodeD <- nodeData(g, nodes(g), "label")

nodeD <- list(`SO:0001968` = "coding_transcript_variant",
              `SO:0001969` = "coding_transcript_intron_variant",
              `SO:0001622` = "UTR_variant",
              `SO:0001623` = "5_prime_UTR_variant",
              `SO:0001624` = "3_prime_UTR_variant",
              `SO:0002090` = "3_prime_UTR_intron_variant",
              `SO:0002091` = "5_prime_UTR_intron_variant")

rename_items <- function(item){
  if (is.list(item)){
    item <- lapply(item,rename_items)
    names(item) <- unname(nodeD[names(item)])
  }
  item
}

tree2 <- rename_items(tree)

结果

# $coding_transcript_variant
# $coding_transcript_variant$UTR_variant
# $coding_transcript_variant$UTR_variant$`3_prime_UTR_variant`
# $coding_transcript_variant$UTR_variant$`3_prime_UTR_variant`$`3_prime_UTR_intron_variant`
# [1] 1
# 
# 
# $coding_transcript_variant$UTR_variant$`5_prime_UTR_variant`
# $coding_transcript_variant$UTR_variant$`5_prime_UTR_variant`$`5_prime_UTR_intron_variant`
# [1] 1
# 
# 
# 
# $coding_transcript_variant$coding_transcript_intron_variant
# $coding_transcript_variant$coding_transcript_intron_variant$`3_prime_UTR_intron_variant`
# [1] 1
# 
# $coding_transcript_variant$coding_transcript_intron_variant$`5_prime_UTR_intron_variant`
# [1] 1

这篇关于使用命名列表重命名列表列表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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