如何在python的列表中返回与输入数字相同的数字位置? [英] How to return the position of numbers, which are same as input numbers, in a list in python?

问题描述

我有一个列表，例如:

[1,2,3,2,1,5,6] 

我想找到列表中1的所有位置.我尝试了if语句，但只得到前1个位置，而不是全部1.

I want to find the all the positions of 1 in the list. I tried if statement, but I only get the position of first 1, not all 1s.

如果使用if语句，则实际输出看起来像[0]，但预期结果应该是[0,4].

The real output if I use if statement looks like [0], but the expected result should be [0,4].

推荐答案

您可以使用列表理解遍历 enumerate(your_list) 并使用if语句作为它仅捕获所需的值，如下所示:

You can use a list comprehension iterating over enumerate(your_list) and using an if statement as part of it to catch only the wanted values, as below:

data = [1,2,3,2,1,5,6] # Your list
num = 1 # The value you want to find indices for

pos = [i for i, v in enumerate(data) if v == num]
print(pos)
# [0, 4]

这篇关于如何在python的列表中返回与输入数字相同的数字位置?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！