将列表元素作为Python中的单个项返回 [英] Return elements of list as individual items in Python

问题描述

Stackoverflow的大家好，

Hi people of Stackoverflow,

我有一个计算列表的函数，我想单独返回列表的每个元素，就像这样(接收此返回值的函数旨在处理未定义数量的参数):

I have a function which calculates a list and I want to return each element of the list individually, like so (the function receiving this return is designed to handle an undefined number of parameters):

def foo():
    my_list = [1,2,3,4]
    return 1,2,3,4

列表中的元素数量未定义，所以我不能这样做:

The number of elements in the list is undefined so I can't do:

return my_list[0], my_list[1], ...

我认为必须有一个简单的解决方案，但是我似乎无法将其束之高阁. 有什么建议?谢谢！

I think there must be an easy solution to this but I can't seem to wrap my head around it. Any suggestions? Thanks!

谢谢您的回答，所以这是我的问题的扩展，这实际上是我的问题:

Thanks for your answers, so here is the extension to my problem, which is really my problem:

def foo():
    my_list = [1,2,3,4]
    return "any_other_value", my_list

所以，我想要的是当我调用foo()，bar = foo()，bar[0] = "any_other_value", bar[1] = 1, bar[2]=3, bar[3] = 4时. my_list的长度不确定(此处只有4个元素).

So, what I want is that when I call foo(), bar = foo(), bar[0] = "any_other_value", bar[1] = 1, bar[2]=3, bar[3] = 4. And my_list is of undetermined length (here it has only 4 elements).

推荐答案

您正在使事情变得过于复杂.只需按您的方式做即可(我想您可以使用tuple(my_list)将其转换为显示方式，但这是不必要的):

You are overcomplicating things. Just do what you were doing as (I suppose you could convert it to how you are showing it with tuple(my_list) but it is unnecessary):

return my_list

这是您需要做的所有事情，因为当您调用带有未定义数量参数的函数时，您可以这样调用它:

This is all you need to do because when you call that function that takes an undefined number of parameters, you can just call it as such:

function_with_undefined_number_of_params(*foo())

*将返回的list解压缩为单独的参数.

The * unpacks the returned list into separate arguments.

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