建立随机乘法示例列表 [英] Building a list of random multiplication examples

问题描述

我有两个100个元素的列表，其中填充了1到10之间的随机数.

I have two 100-element lists filled with random numbers between 1 and 10.

我想列出一个随机选择的数字的乘法，该乘法一直进行到生成大于50的乘积为止.

I want to make a list of multiplications of randomly selected numbers that proceeds until a product greater than 50 is generated.

我如何获得这样一个列表，其中每个元素都是一个产品及其两个因素?

How can I obtain such a list where each element is a product and its two factors?

这是我尝试的代码.我认为它有很多问题.

Here is the code I tried. I think it has a lot of problems.

import random
list1 = []
for i in range(0,1000):
    x = random.randint(1,10)
    list1.append(x)

list2 = []
for i in range(0,1000):
    y = random.randint(1,10)
    list2.append(y)

m=random.sample(list1,1)
n=random.sample(list2,1)

list3=[]
while list3[-1][-1]<50:
    c=[m*n]
    list3.append(m)
    list3.append(n)
    list3.append(c)
print(list3)

我想要的输出

[[5.12154，4.94359，25.3188]，[1.96322，3.46708，6.80663]，[9.40574， 2.28941，21.5336]，[4.61705，9.40964，43.4448]，[9.84915，3.0071，29.6174]，[8.44413，9.50134，80.2305]]

[[5.12154, 4.94359, 25.3188], [1.96322, 3.46708, 6.80663], [9.40574, 2.28941, 21.5336], [4.61705, 9.40964, 43.4448], [9.84915, 3.0071, 29.6174], [8.44413, 9.50134, 80.2305]]

更具描述性:

[[[randomfactor，randomfactor，product]，......，[[randomfactor， randomfactor，大于50]]

[[randomfactor, randomfactor, product],......,[[randomfactor, randomfactor, greater than 50]]

推荐答案

准备两个包含1000个数字的列表，每个列表中的数字从1到10浪费了内存.如果这只是一种简化，而您想从否则得到的列表中提取，只需替换

Prepping two lists with 1000 numbers each with numbers from 1 to 10 in them is wasted memory. If that is just a simplification and you want to draw from lists you got otherwise, simply replace

a,b = random.choices(range(1,11),k=2)

通过

a,b = random.choice(list1), random.choice(list2)

---

import random

result = []
while True:
    a,b = random.choices(range(1,11),k=2)  # replace this one as described above
    c = a*b
    result.append( [a,b,c] )
    if c > 50:
        break

print(result)

输出:

[[9, 3, 27], [3, 5, 15], [8, 5, 40], [5, 9, 45], [9, 3, 27], [8, 5, 40], [8, 8, 64]]

---

如果您需要1到10之间的1000个随机整数，请执行以下操作:

---

If you need 1000 random ints between 1 and 10, do:

random_nums = random.choices(range(1,11),k=1000)

这要快得多，然后循环并附加单个整数1000次.

this if much faster then looping and appending single integers 1000 times.

Doku:

• random.choices(可迭代，k = num_to_draw)

random.choice(可迭代)

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