如何在条件中使用列表 [英] How to use lists in conditionals

问题描述

几个小时前，我问了一个问题，但该问题被重复了.我在问我是否可以使用列表索引来验证答案.这是我的原始代码:

I asked a question a couple of hours ago, but it got closed as a duplicate. I was asking if I could use the index of lists to validate answers. This was my original code:

message = input("Problem: ")
for item in keyword_list:
    if item in message:
        if item == "screen" or item == "cracked" or item == "blank":
            subp.call("screen.txt", shell=True)

...和keyword_list:keyword_list = ["screen", "cracked", "blank"]等...

...and keyword_list: keyword_list = ["screen", "cracked", "blank"] etc....

我被告知(作为对问题的回答):

I got told (as an answer to the question) to do this instead:

message = input("Problem: ")
for item in keyword_list:
    if item in message:
        if item in keyword_list[:3]:
            subp.call("screen.txt", shell=True)

现在不起作用:打开文本文件不起作用，它也不会打开，只是将其跳过，并且如果您输入索引大于0的关键字，则它什么也不会做.

It does not work now: the opening of the text file does not work, it doesn't open, just skips it out, and if you input a keyword with index of more than 0, then it does not do anything.

有人可以告诉我发生了什么事吗?在右目录btw中有一个screen.txt.

Can someone tell me what's happening. There is a screen.txt in the right directory btw.

谢谢:))

推荐答案

您可以执行以下操作:

import subprocess as subp

k = ['screen','cracked','blank']
m = input('Problem:')
for i in k:
    if i in m:
        file = r'C:\somedir\somefile.txt'
        subp.Popen (file, shell=True) 

如果您的列表k很小，那将起作用.如果您的带有关键字的列表很大，则可以通过拆分输入消息m

That will work, if your list k is reasonably small. If your list with keywords is large, then you could do the comparison the other way around by splitting the input message m

import subprocess as subp

k = ['screen','cracked','blank']
m = input('Problem:')
for i in m.split():
    if i in k:
        file = r'C:\somedir\somefile.txt'
        subp.Popen (file, shell=True)  

HTH

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