根据项目值创建一个新列表 [英] Create a new list according to item value

问题描述

我有一个如下列表.

  ['T46', 'T43', 'R45', 'R44', 'B46', 'B43', 'L45', 'L44', 'C46', 'C45']

我要根据int值分组的地方:

where I want to group according to int value:

  [id][' ',' ',' ',' ',' ']   # AREA PATTERN [Top, Right, Bottom, Left, Center]

  [46]['1','0','1','0','1']   #Top,Bottom,Center
  [45]['0','1','0','1','1']   #Right,Left,Center
  [43]['1','0','1','0','0']   #Top,Bottom
  [44]['0','1','0','1','0']   #Right,Left

这可能吗?到目前为止，我尝试过的是:

Is this possible? What I tried so far is:

  id_area = []
  for a in area:
      id = a[1:3]
      areas = a[:1]
      if any(str(id) in s for s in area):
                id_area = #lost

推荐答案

我建议创建一个dict，然后根据整数值映射值

I would suggest creating a dict and then map the values based on the integer value

from collections import defaultdict

mapping = defaultdict(list)
items = ['T46', 'T43', 'R45', 'R44', 'B46', 'B43', 'L45', 'L44', 'C46', 'C45']

for i in items:
    mapping[int(i[1:])].append(i[0])

print(mapping)
>>> defaultdict(<class 'list'>, {43: ['T', 'B'], 44: ['R', 'L'], 45: ['R', 'L', 'C'], 46: ['T', 'B', 'C']})

从那里，您可以用areas创建一个list，然后在dict区域模式中重新分配值

From there, you can create a list with the areas and then reassign the values in your dict the area pattern

areas = ['T', 'L', 'B', 'R', 'C']    
area_pattern = {k: [1 if l in v else 0 for l in areas] for k, v in mapping.items()}

for key, areas in area_pattern.items():
    print(key, areas)

>>> 43 [1, 0, 1, 0, 0]
>>> 44 [0, 1, 0, 1, 0]
>>> 45 [0, 1, 0, 1, 1]
>>> 46 [1, 0, 1, 0, 1]

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