比较不相等的列表 [英] Compare unequal lists

问题描述

我想比较两个不相等的列表:

I want to compare two unequal lists:

a = [6]
b = [6,7,8]

我要关注:

if list a == list b:
   #do something for matching elements from both lists
else:
     #do something for non-matching elements

任何建议都是有意义的.

Any suggestions are appreciative.

推荐答案

如果要查找两个列表中都存在的元素，则应理解以下列表:

If you are looking for the elements which exist in both lists, the following list comprehension should work:

c = [item for item in b if item in a]

像这样:

>>> a = [6]
>>> b = [6,7,8]
>>> c = [item for item in b if item in a]
>>> c
[6]
>>> 

如果需要，说每次值匹配时都打印一些内容，请使用以下for循环:

If you want to, say print something every time the values match, use the following for loop:

for i in b:
    if i in a:
        print '%d in both sets!' %(i)
    else:
        print '%d does not match!' %(i)

运行方式为:

>>> a = [6, 7]
>>> b = [6, 7, 8]
>>> for i in b:
...     if i in a:
...             print '%d in both sets!' %(i)
...     else:
...             print '%d does not match!' %(i)
... 
6 in both sets!
7 in both sets!
8 does not match!
>>> 

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