如何在Silverlight 3中将Canvas用作ItemsControl的ItemsPanel [英] How to use Canvas as the ItemsPanel for an ItemsControl in Silverlight 3

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本文介绍了如何在Silverlight 3中将Canvas用作ItemsControl的ItemsPanel的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用Silverlight 3在ItemsControl DataTemplate中设置Canvas属性.根据

I am trying to set the Canvas properties in an ItemsControl DataTemplate with Silverlight 3. According to this post, the only way of doing that is to set it using the ItemsContainerStyle for the ContentPresenter type, since the Canvas properties only take effect on direct children of the Canvas. This doesn't seem to work in SL3, since the ItemsControl doesn't have an ItemsContainerStyle property, so I tried a ListBox as advised by this article, but it still doesn't work. From the XAML below, I would expect to see a green square, with the numbers 10, 30, 50, 70 cascading from "NW" to "SE" direction. Can anyone tell me why they are all stacked on top of eachother in the NW corner?

<UserControl x:Class="TestControl"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" 
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:System="clr-namespace:System;assembly=mscorlib" >
    <StackPanel>
        <ListBox>
            <ListBox.ItemsPanel>
                <ItemsPanelTemplate>
                    <Canvas Background="Green" Width="100" Height="100" />
                </ItemsPanelTemplate>
            </ListBox.ItemsPanel>
            <ListBox.ItemTemplate>
                <DataTemplate>
                    <TextBox Text="{Binding}" />
                </DataTemplate>                
            </ListBox.ItemTemplate>
            <ListBox.ItemContainerStyle>
                <Style TargetType="ContentPresenter">
                    <Setter Property="Canvas.Left" Value="{Binding}" />
                    <Setter Property="Canvas.Top" Value="{Binding}" />
                </Style>
            </ListBox.ItemContainerStyle>
            <ListBox.Items>
                <System:Int32>10</System:Int32>
                <System:Int32>30</System:Int32>
                <System:Int32>50</System:Int32>
                <System:Int32>70</System:Int32>
            </ListBox.Items>
        </ListBox>
    </StackPanel>
</UserControl>

推荐答案

我不确定它是否适用于您的方案,但是我过去使用RenderTransform做到了这一点.

I'm not sure if it will work in your scenario, but I've accomplished this in the past using the RenderTransform.

<ItemsControl>
    <ItemsControl.ItemsPanel>
        <ItemsPanelTemplate>
            <Canvas Background="Green" />
        </ItemsPanelTemplate>
    </ItemsControl.ItemsPanel>
    <ItemsControl.ItemTemplate>
        <DataTemplate>
            <TextBox Text="{Binding}">
                <TextBox.RenderTransform>
                    <TranslateTransform X="100" Y="100" />
                </TextBox.RenderTransform>
            </TextBox>
        </DataTemplate>
    </ItemsControl.ItemTemplate>
    <ItemsControl.Items>
        <System:Int32>10</System:Int32>
        <System:Int32>30</System:Int32>
        <System:Int32>50</System:Int32>
        <System:Int32>70</System:Int32>
    </ItemsControl.Items>
</ItemsControl>

或者在绑定的情况下,您将需要使用转换器

Or in the case of binding you will need to use a converter

<ItemsControl>
    <ItemsControl.ItemsPanel>
        <ItemsPanelTemplate>
            <Canvas Background="Green" />
        </ItemsPanelTemplate>
    </ItemsControl.ItemsPanel>
    <ItemsControl.ItemTemplate>
        <DataTemplate>
            <TextBox Text="{Binding}" RenderTransform="{Binding Converter={StaticResource NumberToTransformGroupConverter}}" />
        </DataTemplate>
    </ItemsControl.ItemTemplate>
    <ItemsControl.Items>
        <System:Int32>10</System:Int32>
        <System:Int32>30</System:Int32>
        <System:Int32>50</System:Int32>
        <System:Int32>70</System:Int32>
    </ItemsControl.Items>
</ItemsControl>

转换器

public void ConvertTo(object value, ...)
{
    int intValue = int.Parse(value.ToString());

    return new TransformGroup()
    {
        Children = new TransformCollection()
        {
            new TranslateTransform { X = intValue, Y = intValue }
        }
    };
}

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