C#;列表框作为一个对象(容器) [英] C#; listbox's as one object(container)

问题描述

我使用Visual Studio 2008
我的表单上有5个列表框，我创建了一个新的类文件-称为他"scaner.cs"

I use Visual studio 2008
I have 5 listbox's on form,I created a new class file -called him "scaner.cs"

scaner.cs-他看不到列表框".

scaner.cs -he cannot see "listbox".

我已经创建了一个实例.
scaner Comp = new scaner(listBox2, listBox1, listBox3, listBox4, listBox5);

I have create an instance.
scaner Comp = new scaner(listBox2, listBox1, listBox3, listBox4, listBox5);

在scaner.cs文件中，我像这样使用它.

In scaner.cs file I use it like this.

class scaner
    {
        public ListBox ls;
        public ListBox lsE;
        public ListBox lsIVars;
        public ListBox lsNumbers;
        public ListBox lsStrings;

public scaner(ListBox ls, ListBox lsE, ListBox lsIVars, ListBox lsNumbers, ListBox lsStrings)
        {
            this.ls = ls;
            this.lsE = lsE;
            this.lsIVars = lsIVars;
            this.lsNumbers = lsNumbers;
            this.lsStrings = lsStrings;
        }
}

我的问题:如何将这个大代码替换为更舒适"的方法.

My question : How can i replaced this big code to more "comfortably" method.

scaner Comp = new scaner(listBox2, listBox1, listBox3, listBox4, listBox5);

如果我有5个以上的列表框，那将是可怕的. 我如何才能加入另一个类文件列表框" 感谢您的回答.

IF i had more then 5 listbox's ,it will be awful. How can i acced form another class file "Listbox's" Thanks for answers.

推荐答案

创建一个字段来存储所有ListBox实例，然后更改构造函数以接受任意数量的实例:

Create a field to store all the ListBox instances and then change the constructor to accept an arbitrary number of them:

class scaner
{
    readonly IEnumerable<ListBox> listBoxes;

    public IEnumerable<ListBox> ListBoxes
    {
        get { return this.listBoxes; }
    }

    public scaner(params ListBox[] listBoxes)
    {
        this.listBoxes = listBoxes;    
    }
}

这将允许您执行以下操作:

This will allow you to do this:

scaner Comp = new scaner(listBox1, listBox2);

或者这个:

// Here I am passing 4 ListBoxes - you can pass as many as you wish
// without modifying the source code of your scaner class
scaner Comp = new scaner(listBox1, listBox2, listBox3, listBox4);

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