Python元组解压缩 [英] Python Tuple Unpacking

问题描述

如果我有

 nums_and_words = [(1, 'one'), (2, 'two'), (3, 'three')]

并且想要

nums = [1, 2, 3]
words= ['one', 'two', 'three']

我将如何以Pythonic的方式做到这一点?我花了一点时间才知道为什么下面的方法不起作用

How would I do that in a Pythonic way? It took me a minute to realize why the following doesn't work

nums, words = [(el[0], el[1]) for el in nums_and_words]

我很好奇有人是否可以提供类似的方式来达到我想要的结果.

I'm curious if someone can provide a similar manner of achieving the result I'm looking for.

推荐答案

使用 zip ，然后解压:

Use zip, then unpack:

nums_and_words = [(1, 'one'), (2, 'two'), (3, 'three')]
nums, words = zip(*nums_and_words)

实际上，这两次解包":首先，当使用*将列表列表传递给zip时，然后将结果分配给两个变量.

Actually, this "unpacks" twice: First, when you pass the list of lists to zip with *, then when you distribute the result to the two variables.

您可以将zip(*list_of_lists)视为转置"参数:

You can think of zip(*list_of_lists) as 'transposing' the argument:

   zip(*[(1, 'one'), (2, 'two'), (3, 'three')])
== zip(  (1, 'one'), (2, 'two'), (3, 'three') )
== [(1, 2, 3), ('one', 'two', 'three')]

请注意，这将给您元组；如果您确实需要列表，则必须map结果:

Note that this will give you tuples; if you really need lists, you'd have to map the result:

nums, words = map(list, zip(*nums_and_words))

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