嵌套列表中的列表理解 [英] List Comprehension in Nested Lists

问题描述

我有一个类似[["foo", ["a", "b", "c"]], ["bar", ["a", "b", "f"]]]

我想将其拆分出来，这样我就可以计算出As，B等的总数.但是我是Python的新手，并且花了一点时间.

and I'm wanting to split it out so I can get a count of the total number of As, Bs, etc. but I'm new to Python and having a bit of a time of it.

我正在使用[lx for lx in [li[1] for li in fieldlist if li[1]]]尝试获取包含子子列表中所有项目的列表，但是它返回包含第一个子列表的列表([["a", "b", "c"], ["a", "b", "f"]]而不是包含这些子列表内容的列表.我很确定我只是在考虑这个错误，因为我是新的列出理解和Python的人.

I'm using [lx for lx in [li[1] for li in fieldlist if li[1]]] to try and get a list with all of the items in the sub-sublists, but that returns a list with the first sublists ([["a", "b", "c"], ["a", "b", "f"]] instead of a list with the contents of those sublists. I'm pretty sure I'm just thinking about this wrong, since I'm new to list comprehensions and Python.

有人有做到这一点的好方法吗? (是的，我知道我选择的名字(lx，li)太可怕了)

Anyone have a good way to do this? (and yes, I know the names I chose (lx, li) are horrible)

谢谢.

推荐答案

这将为您提供所需的列表:

This will give you the list you want:

[lx for li in fieldlist for lx in li[1] if li[1]]

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